Removing ![]() |
||
So, in the construction of equivalent NFA N' without
Equivalence of NFA and DFA It is worth noting that a DFA is a special type of NFA and hence the class of languages accepted by DFA s is a subset of the class of languages accepted by NFA s. Surprisingly, these two classes are in fact equal. NFA s appeared to have more power than DFA s because of generality enjoyed in terms of Converting DFA to NFA Theorem: Every DFA has as equivalent NFA Proof: A DFA is just a special type of an NFA . In a DFA , the transition functions is defined from![]() ![]() ![]() ![]() |
||