A solid cylinder of 2.4 m diameter and 2.5 kN weight rests on the bottom of a tank which is one meter long. Water and oil (specific gravity 0.75) are poured into the two sides of the cylinder up to a depth of 0.6m and 1.2 m respectively. Find the magnitude of the horizontal and vertical component of the force that keeps the cylinder touching the tank bottom.

Given data: Specific gravity of the oil = 0.75

Diameter of the cylinder = 1.2 m

Sum of horizontal force acting on the cylinder

= 3531.6 N

The vertical force is the volume of water and oil displaced in each side of the cylinder . Vertical force due to water is

V₁ = Water Displaced = m ³
V ₂ = Oil

weight of the cylinder acting downward = 2500N. The sum of vertical forces is 10.15 kN.

Answer: - 3.53 kN. And 10.15 kN.