Example 1 :

Convert a pressure head of 10 m of water column to kerosene of specific gravity 0.8 and carbon-tetra-chloride of specific gravity of 1.62.

Given data:

                Height of water column, h ₁ = 10 m

               Specific gravity of water s₁ = 1.0

                Specific gravity of kerosene s₂ = 0.8

                Specific gravity of carbon-tetra-chloride, s₃ = 1.62

                For the equivalent water head

                Weight of the water column = Weight of the kerosene column.

                So, r g h₁ s₁ = r g h₂ s₂ = r g h₃ s₃

             Answer:-         12.5 m  and   6.17 m.