Module 8: Flow at low and high Reynolds numbers
  Lecture 28: Examples on drag
 
 

But,  is dependent on Reynolds number, which is not known. In such cease, iteration may be required. Assume that the flow is turbulent for the large–size sphere. for flow of a fluid past a sphere is approximately 0.2 (you may like to confirm the data from the graph available in the text)

 

Therefore,

 

Substituting,

 

= 21 m/s >> check Reynolds number

 

For this Reynolds number,   is better approximated at  Therefore,  is re-calculated as . Re–check, which is more accurate than the previous case. For 
, answer is m/s.