Chapter 4 : Second Law of Thermodynamics

Section 4 : Mathematical Statement of the 2nd Law
 
Example 4.3
An ideal gas, Cp = (7/2)R, is heated in a steady-flow heat exchanger from 70°C to 190°C by another stream of the same ideal gas which enters at 320°C. The flow rates of the two streams are the same, and heat losses from the exchanger are negligible. Calculate the molar entropy changes of the two gas streams for both parallel and countercurrent flow in the exchanger. What is ΔStotal in each case?

Temperature drop of stream ‘B’ in either case of flow is the same as the temperature rise of first stream ‘A’ = 120oC.  Thus, exit temperture of stream ‘B’ = 200oC

Thus in both cases:
 

(in both types of flow) =
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