Q12.1. MM parameter for enzyme urease are V_m = 1.33 mol/s.L at E₀ = 5g/L and K_m = 0.266 mol/L.

Q12.1.1. Estimate time needed to remove 95% urea in a 0.5 lit batch vessel containing 0.001 g/L urease.

Q12.2. Competitive Inhibition kinetics : For the model below obtain rate Law
                            
                             E + S ⇔ ES  ; E + I ⇔ EI ; ES ⇒ P + E

Q12.3. Uncompetitive Inhibition kinetics
                           
                            E + S ⇔ ES ; ES + I ⇔ IES ; ES ⇒ P + E

Q12.4. Non- Competitive inhibition : Obtain rate law
                           
                            E + S ⇔ ES ;  ES + I ⇔ IES ;  ES ⇒ P + E ;   E + I ⇔ IE ;  IE + S ⇔ IES

Q12.5. Substrate Inhibition: Obtain rate law

                            E + S ⇔ ES ; ES + S ⇔ SES  ; ES ⇒ P + E

Q12.6 Multiple Steady states in Bioreactors (sourced from Fogler)
Data below is obtained from a CSTR of volume 1000 lit and feed enters at 3.2 lit/ s.

Q12.6.1 Show that the data given is consistent with substrate inhibition model of enzyme kinetics.

s	0	4	8	12	16	20	24	28	32	36	40	44	48	52
rs	0	0.17	0.14	0.11	0.09	0.075	0.07	0.06	0.055	0.05	0.045	0.04	0.037	0.035

S mmol/L, r_s mmol/lit.min. Taken from P7-14 Scott Fogler Element of Chemical Reaction Engineering Prentice Hall 1986.

Q12.6.2. If the Reaction is carried out in a CSTR of volume 1000 lit and feed enters at 3.2 lit/ s.
Find all the steady states. If possible specify which are stable. S₀ = 50 mmol/L.

Q12.6.3. What is the highest conversion possible if operated as above.